Overpass query for search same nearby house numbers

General talk
1

Hello,
I would like to find the same house numbers that are closer than 150 meters via Oparpass Turbo. How to build this? Thanks!

2

Please post the code you already have.

3

Remember they may not be wrong. It depends on your community’s method.

[timeout:55][out:json];
nwr({{bbox}})["addr:housenumber"]["addr:street"]->.all; 
for.all->.thisst(t["addr:street"])
{
  nwr.all(if: t["addr:street"]==thisst.val)->.onthisst;
  for.onthisst->.thisnum(t["addr:housenumber"])
  {
   nwr.onthisst(if: t["addr:housenumber"]==thisnum.val)->.matches;
    if (matches.count(nwr) >= 2)
    {
      foreach.matches->.thismatch
      {
        nwr.matches(around.thismatch:150)->.nearthismatch;
        if (nearthismatch.count(nwr) >= 2)
        {
          (.nearthismatch; - .results;);
          out geom;
          (.nearthismatch; .results;)->.results;
        };
      };
    };
  };
};

In the final process, imagine a situation where 3 addresses are 100m away from each other on a straight line. You need to run around: on all of them to get all results. Can only remove redundant results when outputting. Can’t discard the middle one immediately, as it will cause the last one to be excluded.